AC Signals #1

AC Signals #1

In this lab we analyze sinusoidal signals.

We energize a function generator to 10V at 1kHz

The signal is 10V peak to peak and we get an V_rms of 3.72V

Our calculated V_rms being 3.53 it is within

The complex impedance of the 100-nF capacitor is 1/2*pi*f*C, 159/ohm

Building the circuit, the peak to peak voltage is 8V

Recording the RMS value of the capacitor voltage is 2.93V

These values reconcile and make sense.

The time difference between the two waveforms is 1.8*50us = 90us

Time shift/period * 360 = phi

phi = 32.4

resistor leads the capacitor

We increase f to 10kHz

Zcap = 159.15 ohms

Vcap = 1.52 volts

RMS vaue of the voltage is measured to be .435 volts

these values make sense.

t_x of the two waveforms using cursors = 20us

the phase angle between the two signals = 20us/.1ms*360 = 72 degrees

The peak to peak capacitor voltage is 3.6*2*20 = .144V

V_cap = .046 Vrms

these values reconcile

t_x = 2.5*10us

phi = 90 degrees

R_box = 330 ohms

Vcap = 1.17V

the time difference between the peaks is 18us

phase angle 64.8 degrees

The low range has the highest capacitor voltage

the high range has the smallest capacitor voltage

Since we are filtering out high frequences, it is a low pass filter

resistor always leads the capacitor in phase

at high frequences the phase differences tends to 90 degrees, zero contribution from capacitor.